Odpowiedzi

2010-04-08T20:47:00+02:00

a) Ca(NO3)2

masa: 40g + (14g·2) + (16g·6) = 164g

 

b) Ca(OH)2

masa: 40g + (16g·2) + (1g·2) = 74g


c) CuSO4

masa: 64g + 32g + (16g·4) = 160g 


d) KNO3

masa: 39g + 14g + (16g·3) = 101g

 

2010-04-08T20:50:10+02:00
A) M = 40u + 28u + 96u = 164u
b) M = 40u + 2u + 32u = 74u
c) M = 63,5u + 32u + 64u = 159,5u
d) M = 39u + 14u + 48u = 101u