Odpowiedzi

Najlepsza Odpowiedź!
2010-04-08T22:41:25+02:00
Witaj :) π
dane R/r=k=30, d/D=n=1,2, v=7,9km/s
szukane vx
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d = n *D
m/ [4/3]πr3 = n *M / [4/3]πR3
R3/r3 = n *M/m

v2 = GM/R........[vx]2 = Gm/r
[vx]2/v2 = [m/M]*[R/r].........R3/r3=n*M/m------>[m/M]*[R/r]=n[r2/R2]=n/k2

[vx]2/v2 = n/k2
[vx]2 = v2*n/k2

vx = v*√n /k = 7,9km/s *√(1,2) /30 = 288,5m/s.
Szukana I szybkość kosmiczna wynosi vx = 288,5m/s

Semper in altum...............................pozdrawiam :)




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