Odpowiedzi

2010-04-09T12:44:14+02:00
Δ=25-24
Δ=1
√Δ=1

x1= -5-1/-12 = 1/2
x2= -5+1/-12 = 1/3

x∈(1/3 , 1/2)
2010-04-09T12:49:39+02:00
-6x²+5x-1>0

Δ=b²- 4ac
Δ= 5²- 4*(-6)*(-1)>0
Δ= 25--24
Δ=1
√Δ=1

x1= -b-√Δ/2a

x1= -5-1 /2*(-6)
x1= -6/-12
x1= 1/2

x2= -b+√Δ/2a
x2= -5+1/2*(-6)
x2=-4/-12
x2=1/3