Odpowiedzi

2010-04-09T16:07:48+02:00
X-samochody
y-motocykle

x+y=12
4x+2y=38

x=12-y
4(12-y)+2y=38

x=12-y
48-4y+2y=38

x=12-y
-4y+2y=38-48

x=12-y
-2y=-10|:(-2)

x=12-y
y=5

x=12-5
y=5

x=7
y=5

na parkingu stoi 5 motocykli
41 1 41