Odpowiedzi

2015-07-01T16:17:50+02:00
A - dlugosc boku
a√2 - dlugosc przekatnej
a√2 = a + 5
a\sqrt{2}-a = 5\\a = \frac{5}{\sqrt{2}-1} = \frac{5\sqrt{2}+5}{1} = 5\sqrt{2}+5\\P = a^{2}\\P = (5\sqrt{2}+5)^{2} = 50+50\sqrt{2}+25 = 75+50\sqrt{2}