Odpowiedzi

2010-04-10T15:54:25+02:00
X√2-3=x-√2
x√2-x=-√2+3

x(√2-1)=3-√2/(√2-1)

x= 3-√2/√2-1

x= (3-√2)(√2+1)/2-1= (3√2+3-2-√2)= 2√2+1

3(√2-x)^2+3=(x-3)²
3(2-2√2x+x²)+3= x²-6x+9

6-6√2x+3x²+3=x²-6x+9
2x²-6x(√2-1)=0
x(2x-6√2+6)=0
x=0

2x= 6√2-6/:2
x=3√2-3





(x+1)^3+5=(x-1)^3+(√6x+1)<2> jako potega

x³+3x+3x²+1+5= x³-3x+3x²-1+6x²+2√6x+1

6x+6-6x²-2√6x=0