Odpowiedzi

2010-04-11T14:47:56+02:00
Pole walca = PiR^2 * H

R=3 , H=3

Pole = 3Pi *3 = 9Pi
2 3 2
2010-04-11T14:50:10+02:00
R = 3 cm
H = 3cm
Pb = 2πrH
Pb = 2π*3*3 = 18π cm²
Pc = 2πrH+2πr²
Pc = 2π*3*3+2π*(3)²
Pc = 18π+18π
Pc = 36π cm²
3 3 3
2010-04-11T14:52:30+02:00
3 cm - r koła
3 cm- H

Pp=πr²
Pp= π3²
Pp= 9πcm²

Pb= 2πrH
Pb= 2π3×3
Pb=18πcm²

Pc= 2×9π+ 18π
Pc=36πcm²
Pc=36×3,14=113,04 cm²