Odpowiedzi

2010-04-11T16:12:11+02:00
A.(sina+1)²+(cosa+1)²-3 = sin²a+2sina+1+cos²a+2cosa+1-3=
2sina+2cosa (sin²a+cos²a)=1

b. sin4a-cos4a = (sin²a-cos²a)(sin²a+cos²a)= (sin²a-cos²a)*1