Odpowiedzi

2010-04-11T17:03:55+02:00
⅙ x²- 1⅓x=-2 /*6
x ²-8x=-12
x(1²-8)=-12
-7x=-12
x=1 i 5/7
2010-04-11T17:22:52+02:00
1/6x^2-4/3x=-2/*6
x^2-8x=-12/+12
x^2-8x+12=0

Δ=b^2-4ac
Δ=64-48
Δ=16
√Δ=4

x1=(-b-√Δ)/2a
x1=(8-4)/2
x1=2

x2=(-b+√Δ)/2a
x2=(8+4)/2
x2=6

Odp. x1=2 x2=6