Odpowiedzi

2009-04-26T12:53:20+02:00
X modele janka
3x - modele tomka
3x+16 - modele kasi

x+3x+3x+16=303
7x=287
x=41
3x= 123
3x+16=129

Odp. Janek ma 41 modeli, Tomek ma 123, a kasia 139
2009-04-26T12:53:48+02:00
3x - tomek
x - janek
3x+16 - kasia

3x+x+3x+16=303
7x=287
x=41

tomek ma 3*41 = 123
janek = 41
kasia = 123+16=139
2009-04-26T12:54:38+02:00
J, k, t - liczby modeli janka kasi i tomka

t = 3*j
k = t + 16 = 3*j + 16

k + j + t = 303

(3*j + 16) + (j) + (3*j) = 303
7j + 16 = 303
7j = 303 - 16
7j = 287 / podzielić przez siedem obustronnie
j = 41

t = 3 * 41 = 123

k = 123 + 16 = 139