Odpowiedzi

2010-04-12T18:33:25+02:00
A) MCu(OH)2= 63g/mol+ 2*16g/mol+2*1g/mol=97g/mol

b) MNa2SO4=2*23g/mol+32g/mol+4*16g/mol=142g/mol

c) M3Ca3(PO4)2= 3*3*40g/mol+3*2*31g/mol+3*2*4*16g/mol=930g/mol

d) MC6H12O6=6*12g/mol+12*1g/mol+6*16g/mol=180g/mol