Odpowiedzi

2010-04-13T19:15:15+02:00
MgO=2HNO₃-----Mg(NO₃)₂+H₂O

x=29,6
40=148
x=8g mgo
2010-04-13T19:17:40+02:00
MgO+2HNO₃----->Mg(NO₃)₂+H₂O

masa MgO= 24g+14=40g/mol
masa Mg(NO3)2= 24g+2*[14=(16*3)]=148g/mol
MgO-------->Mg(NO3)2
x g--------->29,6 g
40g/mol--->148 g/mol

x=40 g/mol*29,6 g :148 g/mol
x=8 g MgO
2010-04-13T19:20:05+02:00
MMgO= 16u+24u= 40u
mMg(NO₃)₂= 24u+ 6 x 16u+ 2 x 14u= 24u + 96 u + 28u =148u
29,6 x
____ ___
148 40
x= 29,6* 40/ 148
x= 8g