Odpowiedzi

2010-04-13T19:56:42+02:00
3x-2(x-2)≥3(x-4)-2(2-3x)
3x-2x+4>≥3x-12-4+6x
x+4≥9x-16/-4-9x
-8x≥-20/*(-1)
8x≤20/:8
x≤2,5
1 3 1
2010-04-13T19:58:23+02:00
3x-2(x-2)>3(x-4)-2(2-3x)

3x - 2x + 4 > 3x - 12 - 4 + 6x
3x - 2x - 3x - 6x > -12 - 4 - 4
-8x > -20 / : - 8
x > 2,5

; ]
2010-04-13T19:59:21+02:00
3x-2(x-2)>3(x-4)-2(2-3x)
3x-2x+4>3x-12-4+6x
x+4>9x-16
x-9x>-16-4
-8x>-20 | :(-8)
x>20/8
x>16 i 1/2

*1/2 to ułamek ( jedna druga)