Odpowiedzi

2010-04-14T15:28:52+02:00
A) 3x-2y=2 -> 3(-2y-2) - 2y = 2 -> -6y-6-2y =2 -> -8y = 8 /: (-8) -> y=-1
x+2y=-2 - > x = - 2 - 2y -> x = -2 + 2 = 0

b)3x-4y=0 => 3x - 4 = 0 => 3x = 4 /:3 => x= 4/3
3(1-y)=2(1-y) => 3-3y = 2-2y => -y=-1 / :(-1) => y = 1
2010-04-14T15:32:39+02:00
A) 3x-2y=2
x-2y=-2

3x-2y=2
x=2y-2

3*(-2y -2) -2y=2
x=2y-2

-6y -6-2y=2
x=2y-2

-8y=8 Ι : (-8)
x=2y-2

y=-1
x=2y-2

y=-1
x=2*(-1) -2

y=-1
x=0