Odpowiedzi

2010-04-14T15:35:06+02:00
(2a+3b)+(-3a+b+2)-(-4a-b-3) dla a=4 b =-4
(2*4+3*(-4))+(-3*4-4+2)-(-4*4+4-3)=(8-12)+(-12-2)-(-16+1)=-4-14+15=-3
2010-04-14T15:36:55+02:00
(2*4+3*(-4))+(-3*4+(-4)+2)-(-4*4-(-4)-3)=(8+(-12))+(-12+(-4)+2)-(-16+4-3)=-4+(-14)-(-15)=-3