Odpowiedzi

2010-04-14T18:20:08+02:00
Dane:
T₁ = 20 °C
T₂ = 100 °C
Cw = 4200 [J/kg ×⁰C]
Q = 2 MJ = 2 000 000 J
Rozw.:
Q = m × Cw × ΔT
m = Q / Cw × ΔT
ΔT= T₂ -T₁
m = Q / Cw × (T₂ -T₁ )
m = 2 000 000 J / 4200 [J/kg ×⁰C] × 80 ⁰C = 5,95 kg ≈ 6 kg