Odpowiedzi

2010-04-14T17:25:05+02:00
Dane:
m=2[t]=2000[kg]=2000000[g]=2000000000[mg]=2*10^9[mg];
I=10000[A]=10^4[A];
kAl=0,0932[mg/C].
Wzór:
m=k*I*t II (k*I);
t=m/(k*I);
Jednostka:
[t]=[mg/(mg/C*A)]=[C/A]=[C/(C/s)]=[s].
Obliczenia:
t=2*10^9/(9,32*10^-2*10^4)=(2000*10^6)/932=2.17*10^6[s]=2170000[s].
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