Odpowiedzi

2010-04-14T22:51:03+02:00
X-[x(3+x)-y-a]+(9a-4y+12x) = x-(3x+x²-y-a)+9a-4y+12x = x-3x-x²+y+a + 9a-4y+12x = -x²+x-3x+12x+y-4y+a+9a = x²+10x -3y+10a

x=5
y=9
a=3

(-5)²+10*5-3*9+10*3 = 25+50-27+30 = 78