Odpowiedzi

2010-04-15T08:55:26+02:00
(x-3)(2x-5) < 4x²-2x+20

2x²-5x-6x+15 <4x²-2x+20

2x²-11x+15-4x²+2x-20<0

-2x²-9x-5<0

Δ=81-40=41
√Δ=√41

x₁=9+√41/-4
x₂=9-√41/-4

odp to x₁ i x₂