Odpowiedzi

2010-04-15T14:53:38+02:00

tgα + 1/tgα = 4|:tgα
tgα+1=4tgα|-tgα
1=3tgα|:3
tgα=⅓ i tgα>0

tg²α+(1/tgα)²=1/9+(1:1/3)²=1/9+(1×3)²=1/9+9=9¹₉