Odpowiedzi

2010-04-15T21:51:36+02:00
A)y=c:(2a+z)
y=2a/c + z/c
-z/c = 2a/c - y /*(-c)
z=-2a +yc

b) 1:z + ab = c
1:z = c - ab /*z
1 = z(c-ab) /:(c-ab)
z = 1/c-ab

c) d- (1:za)=b
1:za = b-d /*za
1= za(b-d) /:a(b-d)
z = 1/a(b-d)

d) a-z² = z²c
+z²+z²c = a
z²(1+c)=a /:(1+c)
z² = a/1+c
z = √a: √1+√c

e) az² - bc = c(z²+a)
az² - cz² = ca +bc
z² (a-c) =ca-bc /:(a-c)
z² = (ca-bc):(a-c)
z = √ca-√bc : √a-√c

f) a:b = (1-z²):c
z² = -(a:b)*c + 1
z = - √a:√b* √c + 1