Odpowiedzi

2010-04-15T18:00:38+02:00
Wekt. SB = AB/2 = [-1,2], wiec

punkt B = (4-1, -2+2) = (3;0)

SA = -AB/2 = [1;-2], więc

punkt A = (4+1;-2-2) = (5;-4)

Analogicznie

C = (4+3; -2-1) = (7,-3)

D = (4-3; -2+1) = (1;-1)
1 5 1
2010-04-15T18:22:07+02:00
Jezeli AC = [6,-2] to polowa = 3,-1 bo przekatne przecinaja sie w polowie
SC = [3,-1]
SC = AS
4-3=1
-2-1=-3
wiec A = (1,-3)
4+3=7
-2+1=-1
C=(7,-1)jezeli AB = [-2,4]
1-2=-1
-3+4=1
B(-1,1)
7+2=9
-1-4=-5
D=(9,-5)