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2009-11-06T17:32:49+01:00
II zasada dynamiki : F=ma
m = 3kg
a= vk -v0/t = 8m/s-0m/s / 2s = 8m/s / 2s = 4m/s ^2

F = 3kg * 4m/s^2 = 12 N
1 4 1
2009-11-06T17:48:55+01:00
M=3kg
t=2s
v=8m/s
F=?

F=ma
a= /\V /t=8/2=4 [m/s^2]

F=4m/s^2 * 3kg=12N
1 3 1
2009-11-06T19:12:31+01:00
Dane:m=3kg
t=2s
v=8m/s
Szukane:F=?

F=m*a
a= /\V /t=8/2=4 [m/s^2]

F=4m/s^2 * 3kg=12N
1 5 1