Odpowiedzi

2009-11-08T08:57:39+01:00
12^6 = (12²)³ lub (12³)²

(-1)^8 = ((-1)^4)^2 lub ((-1²)²)²

(-0,5+c)^16 = [[[(-0,5+c)²]²]²]² lub [(-0,5+c)^8]^2 lub [(-0,5+c)^4]^4

(3-a)^32 = [[[[(3-a)²]²]²]²]² lub [(3-a)^2]^16 lub [[[(3-a)^2]^2]^3]^4
4 1 4
2009-11-08T09:35:30+01:00
12⁶ = (12³)²
(-1)⁸ = (-1²)⁴
(-o,5+c) ¹⁶ = [(-0,5)² + c²]⁴
(3-a)³² = [ 3¹⁰-a² ]⁴
3 2 3