Odpowiedzi

2009-11-09T13:50:59+01:00
(x⁶ - y ²) :8.gdzie x=3√2 -1 , y=√2 +1
(x³+y)(x³-y):8
[(3√2 -1)³+√2 +1][(3√2 -1)²-√2-1]:8=
[54√2-54+9√2-1+√2 +1][54√2-54+9√2-1-√2-1]:8=
(64√2-54)(62√2-56):8=(32√2-27)(31√2-28):2=(1982-896√2-837√2+756):2=
991-448√2-418,5√2+378=1369-866,5√2


2009-11-09T13:58:55+01:00
(x⁶ - y²) : 8 = [(3√2 -1)⁶ - (√2 +1)² ] :8 = [(19 -6√2 )³ - 3 -2√2] : 8 =
(6859 - 6498√2 + 4104 - 432√2 - 3 - 2√2) : 8 = (10960- 6932√2) : 8 = 1370 -866,5√2