Odpowiedzi

2011-07-04T14:24:13+02:00

M(Ca(OH)2)=40g/mol+2*16g/mol+2*1g/mol=74g/mol

 

1mol Ca ---------------74g Ca(OH)2

xmol Ca --------------100g Ca(OH)2

 

x=1mol*100g/74g

x=1,4mol

 

 

 

2mol O ---------------74g Ca(OH)2

xmol O --------------100g Ca(OH)2

 

 

x=2mol*100g/74g

x=2,7mol

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2011-07-04T15:02:07+02:00

M_C_a_(_O_H_)_2= 74g/mol

 

 

Obliczam liczbę moli wapnia:

 

1mol Ca--> 74g Ca(OH)₂

x --> 100g Ca(OH)₂

x= 1,35mol

 

Obliczam liczbę moli tlenu

 

2mol O--> 74g Ca(OH)₂

x --> 100g Ca(OH)₂

x= 2,7 mol

 

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