Odpowiedzi

2009-11-09T17:45:36+01:00
5x-(z-x)-2(3x-z)= 5x - z + x - 6x + 2z = 5x + x - 6x - z + 2z = z
1 4 1
2009-11-09T17:47:29+01:00
5x-(z-x)-2(3x-z)= 5x-z-x-6x-2z = 5x+x-6x-z + 2z = z
2009-11-09T17:48:14+01:00