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2010-03-01T00:12:29+01:00
X²-8x+12

delta = b² -4ac = 8²- 4 *12 *1 = 64 -48 = 16
pierwiastek delty = 4

x1= ( -b + pierw.delt.)/2 = (8+4) /2 = 12/2 = 6
x2 = (-b - pierw.delt) /2 = (8-4)/2 =4/2 =2

x²-8x+12 = ( x - 6) ( x -2 )



x²-10x+25

delta = b² -4ac = 10² - 4* 25 *1 = 100 - 100 = 0
x = ( -b) /2a = 10 /2 =5

x²-10x+25 = (x -5)²